(x^2-2x-8)/(4x-x^2)

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Solution for (x^2-2x-8)/(4x-x^2) equation: 


D( x )

4*x-x^2 = 0

4*x-x^2 = 0

4*x-x^2 = 0

4*x-x^2 = 0

DELTA = 4^2-(-1*0*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-4)/(-1*2) or x = (-16^(1/2)-4)/(-1*2)

x = 0 or x = 4

x in (-oo:0) U (0:4) U (4:+oo)

(x^2-(2*x)-8)/(4*x-x^2) = 0

(x^2-2*x-8)/(4*x-x^2) = 0

x^2-2*x-8 = 0

x^2-2*x-8 = 0

DELTA = (-2)^2-(-8*1*4)

DELTA = 36

DELTA > 0

x = (36^(1/2)+2)/(1*2) or x = (2-36^(1/2))/(1*2)

x = 4 or x = -2

(x+2)*(x-4) = 0

4*x-x^2 = 0

x*(4-x) = 0

4-x = 0 // - 4

-x = -4 // * -1

x = 4

x*(x-4) = 0

((x+2)*(x-4))/(x*(x-4)) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-4 )

x-4 = 0 // + 4

x = 4

x in { 4} 

x = -2

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